twin universe cosmology

En résumé (grâce à un LLM libre auto-hébergé)

  • The page explores the cosmology of the twin universe, focusing on the exact solutions of the conjugate stationary metric.
  • It discusses the field equations and internal solutions for massive objects, such as neutron stars or planets.
  • The equations presented describe the internal and external metric, with particular attention to the contributions of pressure and the thermal velocity approximation.

twin universe cosmology Matter ghost matter astrophysics. 2:

Conjugated steady state metrics. Exact solutions. (p2)

3) Schwarzschild-like coupled internal exact solutions.

Consider the case where the fold F* is empty and the Fold F contains a massive object whose mass is M, whose radius is ro, filled by constant mass density r.

It corresponds to the set of equations :
(12)

S = c T

(13) *S = - **c T

with T* = 0. In the classical theory, one derives the internal Schwarzschild solution, giving the T tensor the form :
(14)

The chosen metric form is :
(15)

ds² = en c² dt² - [ el dr² + r² ( dq² + sin²q dj²) ]

In the second members of the differential equations, coming from the field equation we find terms :
(16)

The second corresponds to the contribution of the pressure to the field. It can be neglected for moderate pressures. In the case of a gas it corresponds to the approximation << c, the first being the thermal velocity. If the body is a solid (planet), it means that the pressure contribution is weak, that cannot be asserted if the object is a neutron star. We are going to deal, in the following, with the justified physical assumption :
(17)

Then the differential equation can be written into the simpler form :
(18)

(19)

(20)

c being the Einstein's constant :
(21)

We first add (18) and (19) and get :
(22)

Since c is negative it implies that l' + n' is positive or zero. From the system (18) + (19) + (20) we get :
(23)

(24)

(25)

Write :
(26)

Combining to (23) :

(27)

m(r) is a length, Schwarzschild length like. We refind the status of M(r) as a geometric mass.

(24) can be solved. Write :
(28)

or :
(29)

Introduce :
(30)

we get :
(31)

A being a constant. Then the internal metric becomes :
(32)

When r = ro, the external metric becomes :
(33)

or :
(34)

or :
(35)

The link with the external metric is ensured if :
(36)

Our (p » 0) internal metric solution becomes :
(37)

Notice that we perform expansions into series, according to :
(38)

our internal metric and the classical non zero pressure one [7] :
(39)

fit asymptotically.